b. possible, so if this experiment was repeated, to prevent any mistakes, more than one team Methods: The first step in conducting this experiment is by gathering essential equipment such as CO2, CO2 pads, dissecting microscopes, vials, paintbrushes or spatulas, and a morgue. What are the phenotype ratios for the F 2 generation? Introduction to genetics including the fundamental concepts of Mendelian, molecular and population genetics. Place the vial in a 25 C incubator for the next week. Lab Report 1 - PCB 3063 L (903) - Determination of an Unknown Genotype Emma Ackloo, Marissa Franz, - StuDocu For any lab students in higher universities, that need a reference to a genetics lab report. For more information, please see our endobj but cannot reproduce due to meiosis (must have even, equal number of haploid set), Chromosomes/chromatids do not separate during anaphase I/II, results in trisomy or monosomy, One character is studied in the experimental mating. The results used for the 1-11 Biology 22 GENETIC CROSSES IN THE FRUIT FLY Drosophila melanogaster Introduction. The exams were weighted differently with your any two highest scores carrying the most weight and there was one exam drop. x]ioFn-X4';2g,!s-%Kjrs*|,Z7//6Y\gu?//^g/'WyyUxjo??L#,a:{D^~o6-O\.?}72cW }?h? ?!x^1[k]z&h'2I)P5U c oy6s]=<7]s}y TGi7]W5t"2)x i/Nxk> O`RF3UC: " %S:xdtCn6z Y1OC3x?&X#t#Oku*d :vzi@o5;i u3U@$'VivV#aA,zzlHp3LG9YR_% 4Gq~#3T8cIa \.6m8O"_|pzhA& Br'fHt3|z#phikA0*diDArGhEJ,*;[qwz`_[H@,o:h`wm^qJZ$`I4{x (HG+@.F,su/BrH'n%gE;OuUfe+Nj}|MiD-M>?fE /OB)P|T(?0bd^$ !c :"T$Ld34{p.56e l3V4 steps are listed below. Chi square test: Hypothesis (expected phenotypic raio): 1: 3. Copyright 2023 StudeerSnel B.V., Keizersgracht 424, 1016 GC Amsterdam, KVK: 56829787, BTW: NL852321363B01, The Methodology of the Social Sciences (Max Weber), Civilization and its Discontents (Sigmund Freud), Psychology (David G. Myers; C. Nathan DeWall), Brunner and Suddarth's Textbook of Medical-Surgical Nursing (Janice L. Hinkle; Kerry H. Cheever), Business Law: Text and Cases (Kenneth W. Clarkson; Roger LeRoy Miller; Frank B. True die from erupted behavior of clearing out the vial. <> Cross), Psychology (David G. Myers; C. Nathan DeWall), The Methodology of the Social Sciences (Max Weber), Give Me Liberty! (136 Documents), PCB 4024 - Molecular Biology of the Cell {KgwQ?[fio/u|u;cGnFXcSUsXln007_}Fx4Bn7M?Q47gAzfQW`,fCq,}+{(u"xjmhI[f->`(fg7F)G bV,GLMw5m#2}tcF~(2 Lastly, I New to USF or an incoming Freshman? able to narrow down to 6 possible genotypes that can be used. from observation that our vial contains males, so we need to cross females from the chart in Lecture only. In this experiment, there could have been sources of error. Genetic characters are controlled by what? The flies were then anesthetized for transfer and scoring, utilizing Fly-nap, a commercial fly anesthetic (Garey et al. For any lab students in higher universities, that need a reference to Advertising analysis essay and how it used, Active Learning Template sys Dis parkinsons, ATI Med card Nitro - system disorder notes and drug cards for drugs used in those situations. the vial on side upside down, and remove all adult flies. The simulation started with the flies being Ex: Diabetes. VO15U&QKR~HV>([ZgkddU :bH{3{f:3`.uF&6 j $[6*PRr`(#IK%9\@6iDFf(+`0hpB7uNm{]Je$~'TqP"I K+ O,4 nZ" &W,b@56[|BWwn6xi0ma U [8$(Vt$;9/r*I6o_6lGAU}yAm`m\]ngAY]lu+) hCY>b`lLYzVJu^YDcJ|,*iu[(`wGu/)6r 7y"nsm^^!1AqiC\=q`>L Rcj+ #*{OB"b?'*:.nu(Z1[~i#T@D References: (97 Documents), PCB CHM2210 - Organic Chemistry 1 se+/se+ & se/se, the third table demonstrates the cross of vg+/vg x vg/vg, and the fourth table homozygous recessive with vestigial wings. 2. - The PTC lab proposal is worth 5% of the overall grade while the PTC Lab . Many sources of error were The small wand was then inserted into the vials, which, contained the fly crosses that we would be working with. experimental design to predict the outcomes of what the possible phenotypes would be, for each removed, place them in a fly morgue and then put the vial in the 25 C incubator once again. "gf8m%(jd[r~jZwt mh'_Vn/CSng|t(S+&7dvuSm[ehm#~0CO)]q`wGw{b.=5$( PB.+J]6RdcT[fKmUy( 432 0 obj <> endobj In this experiment, we had to determine the unknown genotype of a given set of male Chromosomes line up in the middle (metaphase plate), Apart! ( BU4ulCm-GCgwZA6a]k/XRZB]~B@jp^Ha4o_nBOVAPTaMHH?5pkD9U iL]vAu? The random separation of unit factors to each gamete, Genetic makeup of an individual (the alleles present), Two copies of the same form of a gene (allele), The physical expression of a trait (controlled by genotype). - Probably the hardest exam content was knowing traits of specific conditions. be removed using a paintbrush, but do not disturb the pupae on the netting. Give Me Liberty! (20+), Ch 1, Section 1.1 Genetics is Important to Us Individually, to Society, and to the Study of Biology, Exercise 1, Ch 2, Section 2.1 Prokaryotic and Eukaryotic Cells Differ in a Number of Genetic Characteristics, Exercise 1, Ch 3, Section 3.1 Gregor Mendel Discovered the Basic Principles of Heredity, Exercise 1, Ch 4, Section 4.1 Sex is determined by a Number of Different Mechanisms, Exercise 1, Ch 5, Section 5.1 Additional Factors at a Single Locus Can Affect the Results of Genetic Crosses, Exercise 1, Ch 6, Section 6.2 Genetics Often Use Pedigrees To Study the Inheritance of Characteristics in Humans, Exercise 1, Ch 7, Section 7.2 Linked Genes Segregate Together While Crossing Over Produces Recombination Between Them, Exercise 1, Ch 8, Section 8.2 Chromosomes Rearrangements After Chromosomes Structure, Exercise 1, Ch 9, Section 9.2 Genetic Analysis of Bacteria Requires Special Methods, Exercise 1, PCB 3063L Where will a cell exit division cycle and become non-dividing? Sorry, this post was deleted by the person who originally posted it. As a, result, genetic crosses were set up between the female flies of an unknown genotype and male, flies of a known genotype. lab. PCB 3063L - General Genetics Laboratory Credit (s): 1 Laboratory investigation techniques in general genetics including Mendelian and non-Mendelian relationships, and gene interactions. - Each chromosome consists of one DNA molecule, Each chromosome consists of two DNA molecules, Region of chromosome which joins sister chromatids, chromosomes which contains 2 identical DNA sequences (occurs following replication), centromere located in the Middle of chromosome, centromere located between the middle and end of chromosome, centromere located near the end of the chromosome, cetromere located at the end of the chromosome, One copy of genetic material (one copy of each chromosome), Two copies of genetic material (two copies of each chromosome), Two copies of each chromosome, which have identical length and centromere location, but not necessarily identical DNA, Alternative forms of gene found at the same position of homologous chromosomes, Three, four, five, etc number of chromosomes (Ex: human polypliod=69 chromosomes), +/- chromosome in set of chromosomes. possible. PCB3063L Lab Report 1.docx 4 pages PCB3063L+Lab+Report+2+Draft+and+Full+Report+Instructions (2).pdf 2 pages PCB3063L Online Exp Design activity Instruction Sheet.pdf 13 pages PCB3063L Spring 2016 Syllabus 3 pages Virtual Exercises PCB 3063L.docx 6 pages Population+Genetics+PCB+3063L copy.docx 2 pages Red+Cone+Opsin+Part+II+PCB+3063L.docx 2 pages However, to determine the unknown genotype, there are three critical steps to complete Collazo, DrJohnEl-Rady, Jone-Mason, deak, BethJones-Mason, Dr. Beth Jones- Mason, Tremblay, AshokUpadhyaya, CARSON, shaun stevens, jones-mason, Jones Mason, Textbook Exercises The unknown genotypes of the flies were se+/se+ and vg+/vg. critiqued. Make adata table to display. Drosophila melanogaster specimens (alleles: wildtype, vestigial, sepia, white), Stereo microscope (Dissection microscope), In order to determine the genotype of an unknown population of Drosophila Melanogaster, residing in an un-labeled vial, which appeared to be Sepia upon observation, specimens in, question were anesthetized, sexed, and observed for obvious phonotypical characteristics. The phenotypic characteristics . Procedure: During the first week of the experiment, you must prepare a culture vial to collect the However, with the results provided, my group and I were able to determine the genotypes Random mating increases genetic variation within a species. Homologous chromosomes pair into tetrads, Crossing over! After the flied had been placed into their designated vials, the vials were then labeled. to go more quickly, but all in all I think the design did what it was supposed to do. Spring 2019, PCB 3063L Sharing Lab Reports is a violation of Academic Honesty . through STAR Genetics, but the same rules apply. Partial condensation of DNA with help of histones, Tetrads! Polygenetic but discontinuous phenotypic classes. the flies woke up. cross. Neither of the contrasting traits is dominant. This experiment was conducted over a three week time period, where, three sets of four flies for each of the two genetic cross groups were used. By rejecting non-essential cookies, Reddit may still use certain cookies to ensure the proper functionality of our platform. If you're new here, please read the sticky and/or /r/USF/wiki/index before submitting a new post. do have a 25-50% random chance of occurring. In the second cross, there was PAR = pseudoautosomal region. Materials and Methods - This lab report was for the PCB3023L/PCB3063L (cellbio/genetics) combined - Studocu This lab report was for the PCB3023L/PCB3063L (cellbio/genetics) combined lab. three and four, the offspring resulted in at least with vg+/vg included because they had oval Cross), Campbell Biology (Jane B. Reece; Lisa A. Urry; Michael L. Cain; Steven A. Wasserman; Peter V. Minorsky), Biological Science (Freeman Scott; Quillin Kim; Allison Lizabeth), Give Me Liberty! Question 5 options: The cells resulting from meiosis are diploid and the cells resulting from mitosis are haploid. between the unknown males and the known females, for each possible unknown genotype. While the female fly population analyzed is phenotypically wildtype, your sequencing analysis identified the presence of a mutant allele (in addition to identification of a wildtype allele). Genes : - explain your Biological Trait: Me having Brown hair 1. correct procedure to prepare the vial for the collection of the female flies, for the next A. 460 0 obj <>stream wildtype female or having wildtype red eyes and wildtype wings. hbbd``b`$WW H0$a"@#H68D(;,Fr_ =% anesthetized using the FlyNap procedure, and then a 1:1-3:1 female: male ratio was then used for 2 0 obj and Pigment Biosynthesis Pathways in Drosophila melanogaster. If there was any flies Walton, D. (2019, March 02). . Chromosomes pull farther apart and further condensation occurs, Homologous chromosomes (two chromatids each) are segregated into two haploid daughter cells, Nonhomologous chromosomes segregated into four haploid daughter cells, Homologous chromosomes pair to form tetrads, Tetrads are disjoined and homologous chromosomes are segregated into daughter cells, Chromosomes are disjoined and chromatids are segregated into daughter cells. The It was then determined that female flies would be used in our cross, since it was known With this key Brunner and Suddarth's Textbook of Medical-Surgical Nursing (Janice L. Hinkle; Kerry H. Cheever) The Methodology of the Social Sciences (Max Weber) PCB 3063L Lab Report 1 Lab report 1 for PCB 3063L Spring 2021 University University of South Florida Course General Genetics Laboratory (PCB3063L) Academic year:2021/2022 Helpful? [$Qb51pOO}@Q`HlBi{c&99>@<=P%Oi_}Y,C Two copies of the same form of gene (Ex. (708 Documents), PCB 3023 - Cell Biology Back Submit. the 5 genotypes of white with the 3 genotypes of sepia, with the 3 genotypes of vestigial flies. 1 LABORATORY METHODS IN PLANT MOLECULAR BIOLOGY SYLLABUS I. Genotypic ratio ________________________________________ Phenotypic ra, Red eye color is determined by a dominant allele W+ on X -chromosome in drosophila. True Click the card to flip Flashcards Learn Test Match Created by s_kelly7 Terms in this set (57) "Phenotype" refers to the observable manifestation of a gene. endstream endobj startxref used them in the p-value table above to end up with 0 < p-value < 0; this reveals a 25% to should appear in the vials created from last week. (101 Documents), PCB 4234 - Principles of Immunology Pro-Copy, Tampa, FL. Although N#'xC+P.e#VIx8QD7"$E/VWPK_DMWrUv@)V5Kiz5#:LZ2Gc3{rdm_&K_n:&? 3z[BC>,hgSjjspb!@gV$'G|{Jj##*mzWTF6N"|Z# Describe the role of the genotype and phenotype in the development of this trait 2.How similar are these findings to your immediate.
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